12 sided die
16
Ṁ4323
Apr 12
0.7%
1
1%
2
1%
3
5%
4
24%
5
32%
6
25%
7
8%
8
1.9%
9
0.5%
10
0.5%
11
0.5%
12

I will roll a 12 sided die until I get six unique numbers. Then, I will find the floor of the average of those six numbers.

Get
Ṁ1,000
and
S3.00
Sort by:
opened a Ṁ500 NO at 1.0% order

To confirm, 6 unique numbers means that the 6 numbers are different.

So: 1,1,1,1,1,1 is not a possible outcomes.

@Daniel_MC correct

🤖

@4fa your random number is: 8

Salt: jj04krnr9o, round: 4946999 (signature 98c2b171d9dfa1c96bfd3634db7405b85ea69ed283023b487a2b121aa7eba2f9d3586ece96eaa517d82a558a14cf321500bc26acb35d8e27d89b116fe177a88560f663463e91c7a76fc9ff953adc520398d3979ce76e991b0d02617d0e2aebab)

🤖

@4fa you asked for a random integer between 1 and 12, inclusive. Coming up shortly!

Source: GitHub, previous round: 4946997 (latest), offset: 2, selected round: 4946999, salt: jj04krnr9o.

@FairlyRandom 12

@YuryKirpichev For transparency, could you openly use FairlyRandom once this market closes? I will demonstrate one usage in my next comment, of course according to the description you will have to do it at least six times.

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